math - Python Dividing number by 99 and then checking if it is equal to number b par 2 digits -
i trying write program first of checks if can number number b swapping 2 digits. below code designed start @ 53150220288 , check if possible reach number 537163806382 changing 2 digits. trying change 2 digits of number 537163806382 new numbers multiples of 99. output them text file. writing program me maths competition.
f = open('blank.txt', 'w') = 53150220288 b = 537163806382 b = str(b) c = 0 while <= 1000000000: in range(len(b)): if b[i] == a[i]: c = c else: c = c + 1 if c == 2: = str(a) print(a, file=f) else: c = 0 = int(a) = + 99 f.close()
problem above code outputs absolutely nothing! don't know why?
your program never enters while loop:
a = 53150220288 while <= 1000000000:
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