user interface - Python, PySide sleep without stalling the whole program? -

i have piece of code:

 self.connect(self.yes_button,signal('clicked()'),self.yes_pressed)  self.connect(self.no_button,signal('clicked()'),self.no_pressed)  def yes_pressed(self):     self.box.append("hello")     time.sleep(2)     self.box.append("text2") 

what when yes button pressed waits 2 seconds first appends both hello , text2(box qtextbrowser() object)how make appending one, wait 2 seconds , append other 1 instead? there simple solution this?

you can this, using pyqt's qtimer. more singleshot

setup : qtimer.singleshot (int msec, qobject receiver, slot()slot() member)

qtcore.qtimer.singleshot(1000, lambda: self.box.append("text2")) #1000 milliseconds = 1 second 

or can event try implementation:

    self.timerscreen = qtimer()     self.timerscreen.setinterval(1000) #1000 milliseconds = 1 second     self.timerscreen.setsingleshot(true)     self.timerscreen.timeout.connect(self.box.append("text2")) 

part 2

you can this, not recommend it:

def testsleep(self):     self.lineedit.settext('start')     qtcore.qtimer.singleshot(10000, lambda: self.box.append("text2"))      qtcore.qtimer.singleshot(10000,lambda: self.timerevent)   def timerevent(self):     qtcore.qtimer.singleshot(10000, lambda: self.box.append("text3")) 

you better off doing this:

x = 10000 #or whatever number qtcore.qtimer.singleshot(10000 + x, lambda: self.box.append("text3"))