c++ - What is difference between int (*p)[3] and int *p[3]? -

this question has answer here:

• c pointer array/array of pointers disambiguation 11 answers

i totally understand "int *p[3]" ( p array of 3 pointer meaning can have 3 different rows of number of ints allocating memory our size of different rows).

my confusion lies " int (*p)[3] " signifies? "p" stores address of 3 contiguous memory of int or else?

please clarify , how use use in program distinguish them.

thanks lot in advance.

@revised 

sorry putting duplicate question. didn't search doubt intensively. doubt still remains novice programmer. went through both pages of q/a c pointer array/array of pointers disambiguation

and

int (*p) [4]?

second link partly clears doubt eliminate doubt please explain above question in reference stack , heap: example

int *p[3]; // (1) 

take 12(3*4bytes) bytes of stack , heap depend on run-time.

int (*p1)[3]; //(2) 

(2) using "new" 1

p1 = new int[7][3]; // (3) 

given in 1 of answer of link int (*p) [4]? ; question since " int (*p1)[3]; //(2) " pointer array of 3 ints how memory taken p1 @ compile time eq(3) can replaced

p1 = new int[n][3]; // (3) n integer

so then?

please explain.

int *p[3];  // type of p int *[3] 

declares p array 3 of int * (i.e., array of 3 int *)

and

int (*p)[3];  // type of p int (*)[3] 

declares p pointer array 3 of int (i.e., pointer array of 3 int)