bash selective filename expansion to pass to daemon -

i want define function or alias starts process daemon can still grok filenames passed it. think:

function emacs() {     daemon /usr/bin/emacs $* } 

this should work for

emacs localfile.txt /tmp/anotherfile.txt 

i need function changes localfile.txt $pwd/localfile.txt , not /tmp/anotherfile.txt. there bash-elegant way this? advice appreciated. if not, thinking of writing in perl.

/iaw

first, if weren't changing arguments, you'd want use "$@", not $*. otherwise spaces cause argument list re-split.

but sure. try this.

function emacs() {   local args=()   in "$@";      case "$a" in [/-]*) args+=("$a");;  # pass options , absolute filenames as-is                      *) args+=("$pwd/$a");; # absolutify else     esac   done   daemon "$(type -p emacs)" "${args[@]}" } 

this still breaks option arguments aren't files, it's start.

however, assumes emacs works daemon, doesn't due lack of controlling terminal. i'm guessing actual application not text editor.. or 1 maintains own window, or something.