c# - .NET Flag Enum get Attributes from values -

greetings stackoverflow,

if i've got enum type flag attribute values in enum type own attributes, how can retrieve of appropriate attributes?

for example:

[flags()] enum myenum {     [enumdisplayname("enum value 1")]     enumvalue1 = 1,     [enumdisplayname("enum value 2")]     enumvalue2 = 2,     [enumdisplayname("enum value 3")]     enumvalue3 = 4, }  void foo() {     var enumvar = myenum.enumvalue2 | myenum.enumvalue3;      // collection of enumdisplayname attribute objects enumvar     ... } 

a quick , dirty way using linq:

ienumerable<enumdisplaynameattribute> attributes =      enum.getvalues(typeof(myenum))         .cast<myenum>()         .where(v => enumvar.hasflag(v))         .select(v => typeof(myenum).getfield(v.tostring()))         .select(f => f.getcustomattributes(typeof(enumdisplaynameattribute), false)[0])         .cast<enumdisplaynameattribute>(); 

or in query syntax:

ienumerable<enumdisplaynameattribute> attributes =      myenum v in enum.getvalues(typeof(myenum))     enumvar.hasflag(v)     let f = typeof(myenum).getfield(v.tostring())     let = f.getcustomattributes(typeof(enumdisplaynameattribute), false)[0]     select ((enumdisplaynameattribute)a); 

alternatively, if there possibly multiple attributes on each field, you'll want this:

ienumerable<enumdisplaynameattribute> attributes =      enum.getvalues(typeof(myenum))         .cast<myenum>()         .where(v => enumvar.hasflag(v))         .select(v => typeof(myenum).getfield(v.tostring()))         .selectmany(f => f.getcustomattributes(typeof(enumdisplaynameattribute), false))         .cast<enumdisplaynameattribute>(); 

or in query syntax:

ienumerable<enumdisplaynameattribute> attributes =      myenum v in enum.getvalues(typeof(myenum))     enumvar.hasflag(v))     let f = typeof(myenum).getfield(v.tostring())     enumdisplaynameattribute in f.getcustomattributes(typeof(enumdisplaynameattribute), false)     select a;